| ⇦ | 
| ⇨ |
The acceleration due to gravity at a place is π² m/sec². Then the time period of a simple pendulum of length one metre is
Options
(a) 2/π sec
(b) 2π sec
(c) 2 sec
(d) π sec
Correct Answer:
2 sec
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - To observed diffraction, the size of the obstacle
- If the value of potential in an A.C circuit is 10 V, the peak value of potential is
- A beam of light contains two wavelengths 6500Å and 5200Å.
- The magnetic susceptibility of a material of a rod is 299. Permeability of vacuum
- The area of cross-section of one limb of an U-tube is twice that of the other.
Topics: Oscillations
(58)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- To observed diffraction, the size of the obstacle
- If the value of potential in an A.C circuit is 10 V, the peak value of potential is
- A beam of light contains two wavelengths 6500Å and 5200Å.
- The magnetic susceptibility of a material of a rod is 299. Permeability of vacuum
- The area of cross-section of one limb of an U-tube is twice that of the other.
Topics: Oscillations (58)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply