| ⇦ |
| ⇨ |
The acceleration due to gravity at a place is π² m/sec². Then the time period of a simple pendulum of length one metre is
Options
(a) 2/π sec
(b) 2π sec
(c) 2 sec
(d) π sec
Correct Answer:
2 sec
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - A U²³⁵ reactor generates power at a rate of P producing 2×10⁸ fission per second.
- A particle moves along the x-axis such that its co-ordinate (x) varies with time (t)
- A light whose frequency is equal to 6.0 x 10¹⁴ Hz is incident on a metal
- A boy standing at top of a tower of 20 m height drops a stone
- The output of OR gate is 1(one)
Topics: Oscillations
(58)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A U²³⁵ reactor generates power at a rate of P producing 2×10⁸ fission per second.
- A particle moves along the x-axis such that its co-ordinate (x) varies with time (t)
- A light whose frequency is equal to 6.0 x 10¹⁴ Hz is incident on a metal
- A boy standing at top of a tower of 20 m height drops a stone
- The output of OR gate is 1(one)
Topics: Oscillations (58)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply