| ⇦ | 
| ⇨ |
The acceleration due to gravity at a place is π² m/sec². Then the time period of a simple pendulum of length one metre is
Options
(a) 2/π sec
(b) 2π sec
(c) 2 sec
(d) π sec
Correct Answer:
2 sec
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - The angle between the dipole moment and electric field at any point on the equatoria
- A wire having resistance 12Ω is bent in the form of an equilateral triangle.
- A lead bullet of 10 gm travelling at 300 m/s strikes against a block
- The maximum and minimum intensities of two sources is 4:1. The ratio of amplitude is
- When a sound wave of wavelength λ is propagating in a medium,
Topics: Oscillations
(58)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The angle between the dipole moment and electric field at any point on the equatoria
- A wire having resistance 12Ω is bent in the form of an equilateral triangle.
- A lead bullet of 10 gm travelling at 300 m/s strikes against a block
- The maximum and minimum intensities of two sources is 4:1. The ratio of amplitude is
- When a sound wave of wavelength λ is propagating in a medium,
Topics: Oscillations (58)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply