| ⇦ | 
| ⇨ |
The 6563 Å line emitted by hydrogen atom in a star is found to be red shifted by 5 Å. The speed with which the star is receding from the earth is
Options
(a) 17.29 x 10⁹ m/s
(b) 4.29 x 10⁷ m/s
(c) 3.39 x 10⁵ m/s
(d) 2.29 x 10⁵ m/s
Correct Answer:
2.29 x 10⁵ m/s
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - An electron of mass m and a photon have same energy E. The ratio of de-Broglie
- A Zenor diode has a contact potential of 1 V in the absence of biasing. It undergoes
- The wavelength of X-rays is in the range
- ₉₂U²³⁴ has 92 protons and 238 nucleons. It decays by emitting an alpha particle
- The radii of circular orbits of two satellites A and B of the earth, are 4R and R
Topics: Wave Optics
(101)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- An electron of mass m and a photon have same energy E. The ratio of de-Broglie
- A Zenor diode has a contact potential of 1 V in the absence of biasing. It undergoes
- The wavelength of X-rays is in the range
- ₉₂U²³⁴ has 92 protons and 238 nucleons. It decays by emitting an alpha particle
- The radii of circular orbits of two satellites A and B of the earth, are 4R and R
Topics: Wave Optics (101)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
question it self is wrong
THE CORRECT ONE WILL BE:
Q: The 6563A∘Hα6563A∘Hα line emitted by hydrogen in a star is found to be red shifted by 15∘A15∘A Estimate the speed with which the star is receding from the earth .
−6.86×105ms−16.86×105ms−1−6.86×10−5ms−16.86×10−5ms−1−6.86×105ms−16.86×105ms−1−6.86×10−5ms−16.86×10−5ms−1
Solution : given : λ=6563∘Aλ=6563∘A
Δλ=15∘AΔλ=15∘A
Δλ=−ΔλλΔλ=−Δλλcc
=−156563=−156563×3×108×3×108
=−6.86×105ms−1=−6.86×105ms−1
Answer : −6.86×105ms−1