| ⇦ | 
| ⇨ |
A Zenor diode has a contact potential of 1 V in the absence of biasing. It undergoes Zenor breakdown for an electric field of 10⁶ V/m at the depletion region of p-n junction. If the width of the depletion region is 2.5 μm, what should be the reverse biased potential for the Zenor breakdown to occur?
Options
(a) 3.5 V
(b) 2.5 V
(c) 1.5 V
(d) 0.5 V
Correct Answer:
2.5 V
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - Calculate the focal length of a reading glass of a person, if the distance
- Two bodies of mass 10 kg and 5 kg moving in concentric orbits of radius
- A 1kg stone at the end of 1 m long string is whirled in a vertical circle at constant speed
- In Young’s double slit experiment, when wavelength used is 6000Å and the screen
- If |A x B|= √3 A.B , then the value of |A + B| is
Topics: Electronic Devices
(124)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Calculate the focal length of a reading glass of a person, if the distance
- Two bodies of mass 10 kg and 5 kg moving in concentric orbits of radius
- A 1kg stone at the end of 1 m long string is whirled in a vertical circle at constant speed
- In Young’s double slit experiment, when wavelength used is 6000Å and the screen
- If |A x B|= √3 A.B , then the value of |A + B| is
Topics: Electronic Devices (124)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
V=E*d
E=10^6 v/m
d=2.5 μm
Therefor V=2.5