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A Zenor diode has a contact potential of 1 V in the absence of biasing. It undergoes Zenor breakdown for an electric field of 10⁶ V/m at the depletion region of p-n junction. If the width of the depletion region is 2.5 μm, what should be the reverse biased potential for the Zenor breakdown to occur?
Options
(a) 3.5 V
(b) 2.5 V
(c) 1.5 V
(d) 0.5 V
Correct Answer:
2.5 V
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
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Topics: Electronic Devices
(124)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Copper and carbon wires are connected in series and the combined resistor is kept
- Function of a rectifier is
- The energy required to charge a parallel plate condenser of plate separation d
- The term liquid crystal refers to a state that is intermediate between
- The angular momentum of an electron is J. The magnitude of the magnetic moment
Topics: Electronic Devices (124)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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V=E*d
E=10^6 v/m
d=2.5 μm
Therefor V=2.5