| ⇦ |
| ⇨ |
The 6563 Å line emitted by hydrogen atom in a star is found to be red shifted by 5 Å. The speed with which the star is receding from the earth is
Options
(a) 17.29 x 10⁹ m/s
(b) 4.29 x 10⁷ m/s
(c) 3.39 x 10⁵ m/s
(d) 2.29 x 10⁵ m/s
Correct Answer:
2.29 x 10⁵ m/s
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - The ratio of the dimensions of planck’s constant and that of the moment of inertia is
- The radius of a planet is twice the radius of earth. Both have almost
- The input characteristics of a transistor in CE mode is the graph obtained by plotting
- The potential energy of a simple harmonic oscillator when the particle is half way
- A thermally insulated rigid container contains an ideal gas heated by a filament
Topics: Wave Optics
(101)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The ratio of the dimensions of planck’s constant and that of the moment of inertia is
- The radius of a planet is twice the radius of earth. Both have almost
- The input characteristics of a transistor in CE mode is the graph obtained by plotting
- The potential energy of a simple harmonic oscillator when the particle is half way
- A thermally insulated rigid container contains an ideal gas heated by a filament
Topics: Wave Optics (101)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

question it self is wrong
THE CORRECT ONE WILL BE:
Q: The 6563A∘Hα6563A∘Hα line emitted by hydrogen in a star is found to be red shifted by 15∘A15∘A Estimate the speed with which the star is receding from the earth .
−6.86×105ms−16.86×105ms−1−6.86×10−5ms−16.86×10−5ms−1−6.86×105ms−16.86×105ms−1−6.86×10−5ms−16.86×10−5ms−1
Solution : given : λ=6563∘Aλ=6563∘A
Δλ=15∘AΔλ=15∘A
Δλ=−ΔλλΔλ=−Δλλcc
=−156563=−156563×3×108×3×108
=−6.86×105ms−1=−6.86×105ms−1
Answer : −6.86×105ms−1