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In the Young’s double slit experiment, a point P on the central bright fringe is such that intensity of point P is 1/4 times the maximum intensity, distance between the slits is d and wavelength λ. Then angular separation of point P is
Options
(a) sin⁻¹ ( λ / d )
(b) sin⁻¹ ( λ / 2d )
(c) sin⁻¹ ( λ / 3d )
(d) sin⁻¹ ( λ / 4d )
Correct Answer:
sin⁻¹ ( λ / 3d )
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
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Topics: Wave Optics
(101)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A deutron is bombarded on ₈O¹⁶ nucleus and α-particle is emitted. The product nucleus is
- The horizontal range of a projectile is 4√3 times the maximum height achieved
- Electric field at a point of distance r from a uniformly charged wire of infinite
- The threshold frequency for a certain photosensitive metal is ν₀. When it is illuminated
- Van der waals,equation of state is(p+a/v²)(V-b)=nRT. The dimensions of a and b
Topics: Wave Optics (101)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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