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Sand is being dropped on a conveyor belt at the rate of M kg/s. The force necessary to keep the belt moving with a constant velocity of v m/s will be:
Options
(a) Mv newton
(b) 2 Mv newton
(c) Mv/2 newton
(d) zero
Correct Answer:
Mv newton
Explanation:
F = d(Mv) / dt = M . dv / dt + v . dM / dt
v is constant,
F = vdM / dt But dM / dt = Mkg / s
F = vM newton.
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Topics: Laws of Motion
(103)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The number of NAND gates required to form an AND gate is
- A bar magnet of pole strength 10 A-m is cut into two equal parts breadthwise.
- In nuclear fusion, two nuclei come together to form a large nucleus.
- Work of 3.0×10⁻⁴ joule is required to be done in increasing the size of a soap film
- The total energy of a simple harmonic oscillator is proportional to
Topics: Laws of Motion (103)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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