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Sand is being dropped on a conveyor belt at the rate of M kg/s. The force necessary to keep the belt moving with a constant velocity of v m/s will be:
Options
(a) Mv newton
(b) 2 Mv newton
(c) Mv/2 newton
(d) zero
Correct Answer:
Mv newton
Explanation:
F = d(Mv) / dt = M . dv / dt + v . dM / dt
v is constant,
F = vdM / dt But dM / dt = Mkg / s
F = vM newton.
Related Questions: - In a P-N junction
- When two small bubbles join to form a bigger one, energy is
- Oil spreads over the surface of water where as water does not spread
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Topics: Laws of Motion
(103)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- In a P-N junction
- When two small bubbles join to form a bigger one, energy is
- Oil spreads over the surface of water where as water does not spread
- A thin wire of length L and mass M is bent to form a semicircle.
- If (range)² is 48 times (maximum height)², then angle of projection is
Topics: Laws of Motion (103)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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