Sand is being dropped on a conveyor belt at the rate of M kg/s. The force necessary

Sand Is Being Dropped On A Conveyor Belt At The Physics Question

Sand is being dropped on a conveyor belt at the rate of M kg/s. The force necessary to keep the belt moving with a constant velocity of v m/s will be:

Options

(a) Mv newton
(b) 2 Mv newton
(c) Mv/2 newton
(d) zero

Correct Answer:

Mv newton

Explanation:

F = d(Mv) / dt = M . dv / dt + v . dM / dt
v is constant,
F = vdM / dt But dM / dt = Mkg / s
F = vM newton.

Related Questions:

  1. A body of mass m=3.513 kg is moving along the x-axis with a speed of 5 m/s
  2. The mass of a lift is 2000kg. When the tension in the supporting cable is 28000N, then its acceleration is
  3. A vibration magnetometer placed in magnetic meridian has a small bar magnet
  4. The electric current in AC circuit is given by the relation i-3 sinωt+4 cos ωt.
  5. A straight conductor 0.1 m long moves in a uniform magnetic field 0.1 T.

Topics: Laws of Motion (103)
Subject: Physics (2479)

Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score

18000+ students are using NEETLab to improve their score. What about you?

Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.

NEETLab Mobile App

Share this page with your friends

Be the first to comment

Leave a Reply

Your email address will not be published.


*