| ⇦ | 
| ⇨ |
Sand is being dropped on a conveyor belt at the rate of M kg/s. The force necessary to keep the belt moving with a constant velocity of v m/s will be:
Options
(a) Mv newton
(b) 2 Mv newton
(c) Mv/2 newton
(d) zero
Correct Answer:
Mv newton
Explanation:
F = d(Mv) / dt = M . dv / dt + v . dM / dt
v is constant,
F = vdM / dt But dM / dt = Mkg / s
F = vM newton.
Related Questions:
- The energy of the em waves is of the order of 15 keV. To which part of the spectrum
- In N-type semi-conductor current is due to
- If the red light is replaced by blue light illuminating the object in a microscope
- A microscope is having objective of focal length 1 cm and eye-piece of focal length 6 cm.
- Photoelectric emision occurs only when the incident light has more than a certain minimum
Topics: Laws of Motion
(103)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply