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Sand is being dropped on a conveyor belt at the rate of M kg/s. The force necessary to keep the belt moving with a constant velocity of v m/s will be:
Options
(a) Mv newton
(b) 2 Mv newton
(c) Mv/2 newton
(d) zero
Correct Answer:
Mv newton
Explanation:
F = d(Mv) / dt = M . dv / dt + v . dM / dt
v is constant,
F = vdM / dt But dM / dt = Mkg / s
F = vM newton.
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Topics: Laws of Motion
(103)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A sound absorber attenuates the sound level by 20 dB. The intensity decreases
- A step-down transformer has 50 turns on secondary and 1000 turns on primary winding.
- A stone tied to the end of a string of 1 m long is whirled in a horizontal circle
- Monochromatic light of frequency 6.0 x 10¹⁴ Hz is produced by a laser. The power emitted
- A road of width 20 m forms an arc of radius 15 m,its outer edge is 2m higher than
Topics: Laws of Motion (103)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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