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Sand is being dropped on a conveyor belt at the rate of M kg/s. The force necessary to keep the belt moving with a constant velocity of v m/s will be:
Options
(a) Mv newton
(b) 2 Mv newton
(c) Mv/2 newton
(d) zero
Correct Answer:
Mv newton
Explanation:
F = d(Mv) / dt = M . dv / dt + v . dM / dt
v is constant,
F = vdM / dt But dM / dt = Mkg / s
F = vM newton.
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Topics: Laws of Motion
(103)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A body of mass m=3.513 kg is moving along the x-axis with a speed of 5 m/s
- The mass of a lift is 2000kg. When the tension in the supporting cable is 28000N, then its acceleration is
- A vibration magnetometer placed in magnetic meridian has a small bar magnet
- The electric current in AC circuit is given by the relation i-3 sinωt+4 cos ωt.
- A straight conductor 0.1 m long moves in a uniform magnetic field 0.1 T.
Topics: Laws of Motion (103)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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