| ⇦ |
| ⇨ |
Pure Si at 300 k has equal electrons (nₑ) and hole (nh) concentrations of 1.5×10⁺¹⁶ m⁻³. Dopping by indium, nh increases to 3×10²² m⁻³. What is nₑ in doped Si?
Options
(a) 2.5×10⁹ m⁻³
(b) 5.5×10⁹ m⁻³
(c) 7.5×10⁹ m⁻³
(d) 6×10⁷ m⁻³
Correct Answer:
7.5×10⁹ m⁻³
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - Masses of three wires of copper are in the ratio of 1:3:5 and their lengths
- A stone falls freely under gravity. It covers distances h1, h2 and h3 in the first 5 secs
- What is the Q-value of the reaction?
¹H+⁷Li→⁴He+⁴He
- The electric potential at a point (x,y,z) is given by V = – x²y – xz³ + 4.
- A circular disc of radius R is removed from a bigger circular disc of radius 2R
Topics: Electronic Devices
(124)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Masses of three wires of copper are in the ratio of 1:3:5 and their lengths
- A stone falls freely under gravity. It covers distances h1, h2 and h3 in the first 5 secs
- What is the Q-value of the reaction? ¹H+⁷Li→⁴He+⁴He
- The electric potential at a point (x,y,z) is given by V = – x²y – xz³ + 4.
- A circular disc of radius R is removed from a bigger circular disc of radius 2R
Topics: Electronic Devices (124)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply