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Periodic time of a satellite revolving above Earth’s surface at a height equal to R, radius of Earth is (g=acceleration due to gravity at Earth’s surface)
Options
(a) 2π√2R/g
(b) 4√2√R/g
(c) 2π√R/g
(d) 8π√R/g
Correct Answer:
4√2√R/g
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
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Topics: Gravitation
(63)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A particle moves along the x-axis from x=0 to x=5 m under the influence of a force
- Two concentric coils each of radius equal to 2π cm are placed at right angles
- A uniform force of (3i + j) newton acfs on a particle of mass 2kg
- For high frequency a capacity offers
- A motorcycle moving with a velocity 72 kmh⁻¹ on a flat road takes a turn
Topics: Gravitation (63)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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