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Periodic time of a satellite revolving above Earth’s surface at a height equal to R, radius of Earth is (g=acceleration due to gravity at Earth’s surface)
Options
(a) 2π√2R/g
(b) 4√2√R/g
(c) 2π√R/g
(d) 8π√R/g
Correct Answer:
4√2√R/g
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
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Topics: Gravitation
(63)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A Si and a Ge diode has identical physical dimensions. The bandgap in Si is larger
- The ratio of the dimensions of planck’s constant and that of the moment of inertia is
- The respective speeds of the molecules are 1,2,3,4 and 5 km/s.
- In Young’s double slit experiment, a third slit is made in between the double slits.
- Two blocks of masses m₁=4 kg and m₂= 2kg are connected to the ends of a string
Topics: Gravitation (63)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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