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Periodic time of a satellite revolving above Earth’s surface at a height equal to R, radius of Earth is (g=acceleration due to gravity at Earth’s surface)
Options
(a) 2π√2R/g
(b) 4√2√R/g
(c) 2π√R/g
(d) 8π√R/g
Correct Answer:
4√2√R/g
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
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Topics: Gravitation
(63)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The velocity v of waves produced in water depends on their wavelength λ, the density
- A rod of weight W is supported by two parallel knife edges A and B is in equilibrium
- A rocket with a lift-off mass 3.5 x 10⁴ kg is blasted upwards with an initial acceleration
- The maximum and minimum magnitudes of the resultant of two vectors
- Two masses of 9 g and 6 g are connected with a string which is passing over a frictionless
Topics: Gravitation (63)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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