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Periodic time of a satellite revolving above Earth’s surface at a height equal to R, radius of Earth is (g=acceleration due to gravity at Earth’s surface)
Options
(a) 2π√2R/g
(b) 4√2√R/g
(c) 2π√R/g
(d) 8π√R/g
Correct Answer:
4√2√R/g
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
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Topics: Gravitation
(63)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A single slit Fraunhogger diffraction pattern is formed with white light.
- A wooden stick 2 m long is floating on the surface of water. The surface tension
- A uniform rope of length 12 m and mass 6 kg hangs vertically from a rigid support.
- The number of photons of wavelength of 540 nm emitted per second by an electric bulb
- Light from the constellation Virgo is observed to increase in wavelength by 0.4%
Topics: Gravitation (63)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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