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Periodic time of a satellite revolving above Earth’s surface at a height equal to R, radius of Earth is (g=acceleration due to gravity at Earth’s surface)
Options
(a) 2π√2R/g
(b) 4√2√R/g
(c) 2π√R/g
(d) 8π√R/g
Correct Answer:
4√2√R/g
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
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Topics: Gravitation
(63)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The refractive index of water, glass and diamond are 1.33, 1.50, 2.40 respectively
- A particle under the action of a constant force moves from rest upto 20 seconds
- An atom bomb works on the principle of
- If the dipole moment of a short bar magnet is 1.25 A-m², the magnetic field on its
- The diameter of the eye ball of a normal eye is about 2.5 cm. The power of the eye
Topics: Gravitation (63)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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