| ⇦ | 
| ⇨ |
In Young’s experiment, the ratio of maximum to minimum intensities of the fringe system is 4:1. The amplitudes of the coherent sources are in the ratio
Options
(a) (4:1)
(b) (3:1)
(c) (2:1)
(d) (1:1)
Correct Answer:
(3:1)
Explanation:
I(max) / I(min) = (ɑ₁ + ɑ₂)² / (ɑ₁ – ɑ₂)²
⇒ 4 / 1 = (ɑ₁ + ɑ₂)² / (ɑ₁ – ɑ₂)²
⇒ (ɑ₁ + ɑ₂) / (ɑ₁ – ɑ₂) = 2 / 1
⇒ ɑ₁ + ɑ₂ = 2 (ɑ₁ – ɑ₂)
⇒ 3ɑ₂ = ɑ₁
⇒ ɑ₁ / ɑ₂ = 3 / 1 = 3 : 1
Related Questions: - A certain mass of Hydrogen is changed to Helium by the process of fusion
- If threshold wevelength for sodium is 6800 Å, the work function will be
- A cricketer can throw a ball to a maximum horizontal distance of 100 m. With the same
- The time period of bar magnet is doubled when magnetic field is reduced
- The Boolean expression P+ P ̅ Q, where P and Q are the inputs of the logic
Topics: Wave Optics
(101)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A certain mass of Hydrogen is changed to Helium by the process of fusion
- If threshold wevelength for sodium is 6800 Å, the work function will be
- A cricketer can throw a ball to a maximum horizontal distance of 100 m. With the same
- The time period of bar magnet is doubled when magnetic field is reduced
- The Boolean expression P+ P ̅ Q, where P and Q are the inputs of the logic
Topics: Wave Optics (101)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply