| ⇦ |
| ⇨ |
In Young’s experiment, the ratio of maximum to minimum intensities of the fringe system is 4:1. The amplitudes of the coherent sources are in the ratio
Options
(a) (4:1)
(b) (3:1)
(c) (2:1)
(d) (1:1)
Correct Answer:
(3:1)
Explanation:
I(max) / I(min) = (ɑ₁ + ɑ₂)² / (ɑ₁ – ɑ₂)²
⇒ 4 / 1 = (ɑ₁ + ɑ₂)² / (ɑ₁ – ɑ₂)²
⇒ (ɑ₁ + ɑ₂) / (ɑ₁ – ɑ₂) = 2 / 1
⇒ ɑ₁ + ɑ₂ = 2 (ɑ₁ – ɑ₂)
⇒ 3ɑ₂ = ɑ₁
⇒ ɑ₁ / ɑ₂ = 3 / 1 = 3 : 1
Related Questions: - The magnetic susceptibility is negative for
- The diameter of the eye ball of a normal eye is about 2.5 cm. The power of the eye
- Dimensions of resistance in an electrical circuit, in terms of dimension of mass M,
- Certain quantity of water cools from 70⁰ C to 60⁰C in the first 5 minutes and to 54⁰C
- Shear modulus is zero for
Topics: Wave Optics
(101)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The magnetic susceptibility is negative for
- The diameter of the eye ball of a normal eye is about 2.5 cm. The power of the eye
- Dimensions of resistance in an electrical circuit, in terms of dimension of mass M,
- Certain quantity of water cools from 70⁰ C to 60⁰C in the first 5 minutes and to 54⁰C
- Shear modulus is zero for
Topics: Wave Optics (101)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply