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In Young’s experiment, the ratio of maximum to minimum intensities of the fringe system is 4:1. The amplitudes of the coherent sources are in the ratio
Options
(a) (4:1)
(b) (3:1)
(c) (2:1)
(d) (1:1)
Correct Answer:
(3:1)
Explanation:
I(max) / I(min) = (ɑ₁ + ɑ₂)² / (ɑ₁ – ɑ₂)²
⇒ 4 / 1 = (ɑ₁ + ɑ₂)² / (ɑ₁ – ɑ₂)²
⇒ (ɑ₁ + ɑ₂) / (ɑ₁ – ɑ₂) = 2 / 1
⇒ ɑ₁ + ɑ₂ = 2 (ɑ₁ – ɑ₂)
⇒ 3ɑ₂ = ɑ₁
⇒ ɑ₁ / ɑ₂ = 3 / 1 = 3 : 1
Related Questions: - Two particles which are initially at rest, move towards each other
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Topics: Wave Optics
(101)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Two particles which are initially at rest, move towards each other
- When one of the slits of Young’s experiment is covered with a transport sheet
- The sun light reaches us as white and not as its components because
- A transistor is working in common emitter mode. Its amplification factor is 80
- What is the voltage gain in a common-emiiter amplifier, when input resistance is 4 Ω
Topics: Wave Optics (101)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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