⇦ | ⇨ |
In Young’s double slit experiment, the fringe width is 1×10⁻⁴ m, if the distance between the slit and screen is doubled and the distance between two slits is reduced to half and the wavelength is changed from 6.4×10⁻⁷ m to 4.0×10⁻⁷ m, then the value of new fringe width will be
Options
(a) 2.5×10⁻⁴ m
(b) 2.0×10⁻⁴ m
(c) 1×10⁻⁴ m
(d) 0.5×10⁻⁴ m
Correct Answer:
2.5×10⁻⁴ m
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - Two spherical nuclei have mass numbers 216 and 64 with their radii R₁ and R₂,
- When a metallic surface is illuminated with radiation of wavelength λ,
- In a uniform circular motion, work done in one complete rotation is
- The power supplied by a force acting on a particle moving in a straight line
- In the middle of the depletion layer of a reverse-biased P-N junction, the
Topics: Wave Optics
(101)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Two spherical nuclei have mass numbers 216 and 64 with their radii R₁ and R₂,
- When a metallic surface is illuminated with radiation of wavelength λ,
- In a uniform circular motion, work done in one complete rotation is
- The power supplied by a force acting on a particle moving in a straight line
- In the middle of the depletion layer of a reverse-biased P-N junction, the
Topics: Wave Optics (101)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply