| ⇦ |
| ⇨ |
In Young’s double slit experiment, the fringe width is 1×10⁻⁴ m, if the distance between the slit and screen is doubled and the distance between two slits is reduced to half and the wavelength is changed from 6.4×10⁻⁷ m to 4.0×10⁻⁷ m, then the value of new fringe width will be
Options
(a) 2.5×10⁻⁴ m
(b) 2.0×10⁻⁴ m
(c) 1×10⁻⁴ m
(d) 0.5×10⁻⁴ m
Correct Answer:
2.5×10⁻⁴ m
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - The wavelength of the matter wave is independent of
- If two vectors are equal in magnitude and their resultant is also equal in magnitude
- Energy of photon whose frequency is 10¹² MHz will be
- A mass of 2.0 kg is put on a flat plan attached to a vertical spring fixed on the ground
- A condenser of capacity C is charged to a potential difference of V₁. The plates
Topics: Wave Optics
(101)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The wavelength of the matter wave is independent of
- If two vectors are equal in magnitude and their resultant is also equal in magnitude
- Energy of photon whose frequency is 10¹² MHz will be
- A mass of 2.0 kg is put on a flat plan attached to a vertical spring fixed on the ground
- A condenser of capacity C is charged to a potential difference of V₁. The plates
Topics: Wave Optics (101)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply