| ⇦ | 
| ⇨ |
In Young’s double slit experiment, the fringe width is 1×10⁻⁴ m, if the distance between the slit and screen is doubled and the distance between two slits is reduced to half and the wavelength is changed from 6.4×10⁻⁷ m to 4.0×10⁻⁷ m, then the value of new fringe width will be
Options
(a) 2.5×10⁻⁴ m
(b) 2.0×10⁻⁴ m
(c) 1×10⁻⁴ m
(d) 0.5×10⁻⁴ m
Correct Answer:
2.5×10⁻⁴ m
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - An avarage induced e.m.f. of 1 V appears in a coil when the current in it is changed
- Laser light is considered to be coherant because it consists of
- Electron in hydrogen atom first jumps from third excited state to second excited
- Which of the following transitions in hydrogen atoms emit photons of highest frequency?
- Thomson coefficient of a conductor is 10 µV/K. Its two ends are kept
Topics: Wave Optics
(101)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- An avarage induced e.m.f. of 1 V appears in a coil when the current in it is changed
- Laser light is considered to be coherant because it consists of
- Electron in hydrogen atom first jumps from third excited state to second excited
- Which of the following transitions in hydrogen atoms emit photons of highest frequency?
- Thomson coefficient of a conductor is 10 µV/K. Its two ends are kept
Topics: Wave Optics (101)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply