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In Young’s double slit experiment the distance between the slits and the screen is doubled. The separation between the slits is reduces to half. As a result the fringe width
Options
(a) is doubled
(b) is halved
(c) becomes four times
(d) remains unchanged
Correct Answer:
becomes four times
Explanation:
Fringe width β = Dλ/d;
From qn D’ = 2D and d’ = d/2
β’ = λD¹ / d¹ = 4β
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Topics: Ray Optics
(94)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The half life of a radioactive isotope ‘X’ is 20 years. It decays to another element Y
- A body is moving with velocity 30 m/s towards east. After 10 seconds its velocity
- Consider a uniform square plate of side ɑ and mass m. The moment of inertia
- Two capacitors of 10pF and 20pF are connected to 200V and 100V sources, respectively.
- A fringe width of a certain interference pattern is β=0.002 cm. What is the distance
Topics: Ray Optics (94)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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