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In the series resonance the value of impedence is 3 Ω and the resistance is 4Ω, then the value of power factor of the circuit is
Options
(a) (4/3)
(b) (3/4)
(c) zero
(d) infinity
Correct Answer:
(4/3)
Explanation:
Power factor cos ɸ = Resistance / Impedance = 4 / 3.
Related Questions: - Point masses m₁ and m₂ are placed at the opposite ends of a rigid rod of length L,
- Zenor breakdown will occur if
- Application of a forward bias to a P-N junction
- An electric dipole placed in a non-uniform electric field experiences
- Copper has face centered cubic (fcc) lattice with interatomic spacing equal to 2.54Å.
Topics: Alternating Current
(96)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Point masses m₁ and m₂ are placed at the opposite ends of a rigid rod of length L,
- Zenor breakdown will occur if
- Application of a forward bias to a P-N junction
- An electric dipole placed in a non-uniform electric field experiences
- Copper has face centered cubic (fcc) lattice with interatomic spacing equal to 2.54Å.
Topics: Alternating Current (96)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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