| ⇦ | 
| ⇨ |
A thin semicircular conducting ring (PQR) of radius r is falling with its plane vertical in a horizontal magnetic field B, as shown in the figure. The potential difference developed across the ring when its speed is v, is
Options
(a) zero
(b) Bvπr²/2 and P is at higher potential
(c) πrBv and R is at higher potential
(d) 2rBv and R is at higher potential
Correct Answer:
2rBv and R is at higher potential
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - The radius of the convex surface of a plano-convex lens is 20 cm and the refractive index
- The ‘rad’ is the correct unit used to report the measurement of
- The angular momentum of an electron is J. The magnitude of the magnetic moment
- Two satellites of earth, S₁ and S₂ are moving in the same orbit. The mass of S₁
- If M (A; Z), Mₚ and Mₙ denote the masses of the nucleus AZ X, proton
Topics: Electromagnetic Induction
(76)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The radius of the convex surface of a plano-convex lens is 20 cm and the refractive index
- The ‘rad’ is the correct unit used to report the measurement of
- The angular momentum of an electron is J. The magnitude of the magnetic moment
- Two satellites of earth, S₁ and S₂ are moving in the same orbit. The mass of S₁
- If M (A; Z), Mₚ and Mₙ denote the masses of the nucleus AZ X, proton
Topics: Electromagnetic Induction (76)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply