| ⇦ | 
| ⇨ |
A thin semicircular conducting ring (PQR) of radius r is falling with its plane vertical in a horizontal magnetic field B, as shown in the figure. The potential difference developed across the ring when its speed is v, is
Options
(a) zero
(b) Bvπr²/2 and P is at higher potential
(c) πrBv and R is at higher potential
(d) 2rBv and R is at higher potential
Correct Answer:
2rBv and R is at higher potential
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - The order of radius of the nucleus of an atom is
- If in a nuclear fusion process, the masses of the fusing nuclei be m₁ and m₂
- A super conductor exhibits perfect
- In p- type semiconductor, the acceptor level lies
- The total energy of an electron in the first excited state of hydrogen atom
Topics: Electromagnetic Induction
(76)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The order of radius of the nucleus of an atom is
- If in a nuclear fusion process, the masses of the fusing nuclei be m₁ and m₂
- A super conductor exhibits perfect
- In p- type semiconductor, the acceptor level lies
- The total energy of an electron in the first excited state of hydrogen atom
Topics: Electromagnetic Induction (76)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply