⇦ | ⇨ |
In the reaction ₉₂U²³⁴→₈₇Y²²², how many α-particle and β-particles are emitted respectively?
Options
(a) 3,5
(b) 5,3
(c) 3,3
(d) 3,1
Correct Answer:
3,1
Explanation:
Change in A = 234 – 222 = 12
This is the effect of 3 α-particles = 3 × ₂He⁴
Change in Z due to 3α = -6
Given change in Z = 87 – 92 = -5
Hence one beta is emitted = -6 + 1 = -5
Therefore, 3α and 1β
Related Questions: - A radioactive element forms its own isotope after 3 consecutive disintegrations.
- A cord is wound round the circumference of wheel of radius
- Height of geostationary satellite is
- An adiabatic process occurs at constant
- The molar specific heat at constant pressure of an ideal gas is (7/2)R. The ratio
Topics: Radioactivity
(83)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A radioactive element forms its own isotope after 3 consecutive disintegrations.
- A cord is wound round the circumference of wheel of radius
- Height of geostationary satellite is
- An adiabatic process occurs at constant
- The molar specific heat at constant pressure of an ideal gas is (7/2)R. The ratio
Topics: Radioactivity (83)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply