| ⇦ |
| ⇨ |
In the reaction ₉₂U²³⁴→₈₇Y²²², how many α-particle and β-particles are emitted respectively?
Options
(a) 3,5
(b) 5,3
(c) 3,3
(d) 3,1
Correct Answer:
3,1
Explanation:
Change in A = 234 – 222 = 12
This is the effect of 3 α-particles = 3 × ₂He⁴
Change in Z due to 3α = -6
Given change in Z = 87 – 92 = -5
Hence one beta is emitted = -6 + 1 = -5
Therefore, 3α and 1β
Related Questions: - The power factor of an AC circuit having resistance R and inductance L connected
- A magnetic field of 1600 A/m produces a magnetic flux of 2.4 x 10⁻⁵ Wb
- A 36 Ω galvanometer is shunted by resistance of 4 Ω. The percentage of the total current
- A source of unknown frequency gives 4 beats/s, when sounded with a source harmonic
- A bus is moving with a speed of 10 ms⁻¹ on a straight road
Topics: Radioactivity
(83)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The power factor of an AC circuit having resistance R and inductance L connected
- A magnetic field of 1600 A/m produces a magnetic flux of 2.4 x 10⁻⁵ Wb
- A 36 Ω galvanometer is shunted by resistance of 4 Ω. The percentage of the total current
- A source of unknown frequency gives 4 beats/s, when sounded with a source harmonic
- A bus is moving with a speed of 10 ms⁻¹ on a straight road
Topics: Radioactivity (83)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply