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In the reaction ₉₂U²³⁴→₈₇Y²²², how many α-particle and β-particles are emitted respectively?
Options
(a) 3,5
(b) 5,3
(c) 3,3
(d) 3,1
Correct Answer:
3,1
Explanation:
Change in A = 234 – 222 = 12
This is the effect of 3 α-particles = 3 × ₂He⁴
Change in Z due to 3α = -6
Given change in Z = 87 – 92 = -5
Hence one beta is emitted = -6 + 1 = -5
Therefore, 3α and 1β
Related Questions: - If in a nuclear fusion process, the masses of the fusing nuclei be m₁ and m₂
- When an α-particle of mass m moving with velocity ν bombards on a heavy nucleus
- The cylindrical tube of a spray pump has radius R, one end of which has n fine holes,
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Topics: Radioactivity
(83)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- If in a nuclear fusion process, the masses of the fusing nuclei be m₁ and m₂
- When an α-particle of mass m moving with velocity ν bombards on a heavy nucleus
- The cylindrical tube of a spray pump has radius R, one end of which has n fine holes,
- The period of oscillation of a mass M suspended from a spring of negligible mass is T
- A thin wire of length L and mass M is bent to form a semicircle.
Topics: Radioactivity (83)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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