In hydrogen atom, energy of first excited state is –3.4 eV. Find out KE

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In hydrogen atom, energy of first excited state is –3.4 eV. Find out KE of the same orbit of Hydrogen atom

Options

(a) +3.4 eV
(b) +6.8 eV
(c) –13.6 eV
(d) +13.6 eV

Correct Answer:

+3.4 eV

Explanation:

No explanation available. Be the first to write the explanation for this question by commenting below.

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Question Type: Memory (964)
Difficulty Level: Easy (1008)
Topics: Structure of Atom (90)
Subject: Chemistry (2512)

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