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6.02 x 10²° molecules of urea are present in 100 mL of its solution. The concentration of the solution is
Options
(a) 0.01 M
(b) 0.001 M
(c) 0.1 M
(d) 0.02 M
Correct Answer:
0.01 M
Explanation:
M= (6.02 x 10²° x 1000) / (100 x 6.02 x 10²³)
=0.01 M
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Question Type: Memory
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Difficulty Level: Easy
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Topics: Basic Concepts of Chemistry
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Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- One litre hard water contains 12 mg Mg²⁺. Milli equivalents of washing soda
- Number of moles of MnO₄⁻ required to oxidize one mole of ferrous oxalate
- Molar volume of CO₂ is maximum at
- Azeotropic mixture of HCl and H₂O has
- Which of the following aqueous acid is most acidic
Question Type: Memory (964)
Difficulty Level: Easy (1008)
Topics: Basic Concepts of Chemistry (94)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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