| ⇦ | 
| ⇨ |
6.02 x 10²° molecules of urea are present in 100 mL of its solution. The concentration of the solution is
Options
(a) 0.01 M
(b) 0.001 M
(c) 0.1 M
(d) 0.02 M
Correct Answer:
0.01 M
Explanation:
M= (6.02 x 10²° x 1000) / (100 x 6.02 x 10²³)
=0.01 M
Related Questions: - Which one of the following statements about transition elements is incorrect
- An organic compound gives Molisch’s test as well as Benedict’s test.
- which of the following is an example of thermosetting polymer
- Para and ortho-hydrogen differ in
- The number of moles of KMnO₄ reduced by one mole of KI in alkaline medium is
Question Type: Memory
(964)
Difficulty Level: Easy
(1008)
Topics: Basic Concepts of Chemistry
(94)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Which one of the following statements about transition elements is incorrect
- An organic compound gives Molisch’s test as well as Benedict’s test.
- which of the following is an example of thermosetting polymer
- Para and ortho-hydrogen differ in
- The number of moles of KMnO₄ reduced by one mole of KI in alkaline medium is
Question Type: Memory (964)
Difficulty Level: Easy (1008)
Topics: Basic Concepts of Chemistry (94)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply