| ⇦ | 
| ⇨ |
In hydrogen atom, energy of first excited state is –3.4 eV. Find out KE of the same orbit of Hydrogen atom
Options
(a) +3.4 eV
(b) +6.8 eV
(c) –13.6 eV
(d) +13.6 eV
Correct Answer:
+3.4 eV
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - For isothermal change in the case of an ideal gas
- Which of the following carbonyls will have the strongest C – O bond
- Which of the following has ability to release bromine from potassium bromide
- At 25⁰C, the dissociation constant of a base, BOH, is 1.0 ˣ 10⁻¹².
- Zeolite used to soften hardness of water is, hydrated
Question Type: Memory
(964)
Difficulty Level: Easy
(1008)
Topics: Structure of Atom
(90)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- For isothermal change in the case of an ideal gas
- Which of the following carbonyls will have the strongest C – O bond
- Which of the following has ability to release bromine from potassium bromide
- At 25⁰C, the dissociation constant of a base, BOH, is 1.0 ˣ 10⁻¹².
- Zeolite used to soften hardness of water is, hydrated
Question Type: Memory (964)
Difficulty Level: Easy (1008)
Topics: Structure of Atom (90)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Kinetic energy = negative of total energy or
-(-3.4)=3.4
I hope u like my explanation 😇