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In hydrogen atom, energy of first excited state is –3.4 eV. Find out KE of the same orbit of Hydrogen atom
Options
(a) +3.4 eV
(b) +6.8 eV
(c) –13.6 eV
(d) +13.6 eV
Correct Answer:
+3.4 eV
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
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Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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- If 10 cm³ solution of H₂O₂ ,on decomposition gives 150 cm³ of O₂
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Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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Kinetic energy = negative of total energy or
-(-3.4)=3.4
I hope u like my explanation 😇