In hydrogen atom, energy of first excited state is –3.4 eV. Find out KE

⇦

⇨

In hydrogen atom, energy of first excited state is –3.4 eV. Find out KE of the same orbit of Hydrogen atom

Options

(a) +3.4 eV
(b) +6.8 eV
(c) –13.6 eV
(d) +13.6 eV

Correct Answer:

+3.4 eV

Explanation:

No explanation available. Be the first to write the explanation for this question by commenting below.

Related Questions:

1. Chloride ion and potassium ion are isoelectronic. Then
2. Which of the following pairs of transition metal ions are the stronger oxidisi
3. The oxidation state of nitrogen is highest in
4. Which of the following is a redox reaction
5. The rate of reactions exhibiting negative activation energy

Question Type: Memory (964)
Difficulty Level: Easy (1008)
Topics: Structure of Atom (90)
Subject: Chemistry (2512)

---

Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score

18000+ students are using NEETLab to improve their score. What about you?

Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.

---

Share this page with your friends