| ⇦ |
| ⇨ |
In hydrogen atom, energy of first excited state is –3.4 eV. Find out KE of the same orbit of Hydrogen atom
Options
(a) +3.4 eV
(b) +6.8 eV
(c) –13.6 eV
(d) +13.6 eV
Correct Answer:
+3.4 eV
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - In tetragonal crystal system, which of following is not true
- Which statement is incorrect
- Which of the following is the strongest oxidising agent
- The presence of colloidal particles can be confirmed with the help of
- Rectified spirit has ethanol
Question Type: Memory
(964)
Difficulty Level: Easy
(1008)
Topics: Structure of Atom
(90)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- In tetragonal crystal system, which of following is not true
- Which statement is incorrect
- Which of the following is the strongest oxidising agent
- The presence of colloidal particles can be confirmed with the help of
- Rectified spirit has ethanol
Question Type: Memory (964)
Difficulty Level: Easy (1008)
Topics: Structure of Atom (90)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Kinetic energy = negative of total energy or
-(-3.4)=3.4
I hope u like my explanation 😇