| ⇦ | 
| ⇨ |
In hydrogen atom, energy of first excited state is –3.4 eV. Find out KE of the same orbit of Hydrogen atom
Options
(a) +3.4 eV
(b) +6.8 eV
(c) –13.6 eV
(d) +13.6 eV
Correct Answer:
+3.4 eV
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - The plot of concentration of the reactant vs time for a reaction is a straight
- Allyl chloride on dehydrochlorination gives
- The compounds having only primary hydrogen atoms is
- At 25⁰C, the dissociation constant of a base, BOH, is 1.0 ˣ 10⁻¹².
- A given metal crystallizes out with a cubic structure having edge length of 361 pm.
Question Type: Memory
(964)
Difficulty Level: Easy
(1008)
Topics: Structure of Atom
(90)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The plot of concentration of the reactant vs time for a reaction is a straight
- Allyl chloride on dehydrochlorination gives
- The compounds having only primary hydrogen atoms is
- At 25⁰C, the dissociation constant of a base, BOH, is 1.0 ˣ 10⁻¹².
- A given metal crystallizes out with a cubic structure having edge length of 361 pm.
Question Type: Memory (964)
Difficulty Level: Easy (1008)
Topics: Structure of Atom (90)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Kinetic energy = negative of total energy or
-(-3.4)=3.4
I hope u like my explanation 😇