| ⇦ | 
| ⇨ |
In hydrogen atom, energy of first excited state is –3.4 eV. Find out KE of the same orbit of Hydrogen atom
Options
(a) +3.4 eV
(b) +6.8 eV
(c) –13.6 eV
(d) +13.6 eV
Correct Answer:
+3.4 eV
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - 5 mL of N HCl, 20 mL of N/2 H₂SO₄ and 30 mL of N/3 HNO₃ are mixed together
- Which one of the following compounds is not a protonic acid?
- Diazo-coupling is useful to prepare some
- What is the entropy change (in J K⁻¹ mol⁻¹) when one mole of ice is converted
- Which of the following species contains three bond pairs and one lone pair
Question Type: Memory
(964)
Difficulty Level: Easy
(1008)
Topics: Structure of Atom
(90)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- 5 mL of N HCl, 20 mL of N/2 H₂SO₄ and 30 mL of N/3 HNO₃ are mixed together
- Which one of the following compounds is not a protonic acid?
- Diazo-coupling is useful to prepare some
- What is the entropy change (in J K⁻¹ mol⁻¹) when one mole of ice is converted
- Which of the following species contains three bond pairs and one lone pair
Question Type: Memory (964)
Difficulty Level: Easy (1008)
Topics: Structure of Atom (90)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Kinetic energy = negative of total energy or
-(-3.4)=3.4
I hope u like my explanation 😇