| ⇦ | 
| ⇨ |
In an isobaric process,when temperature changes from T₁ to T₂, ΔS is equal to
Options
(a) 2.303 Cp log (T₂/T₁)
(b) 2.303 Cp ln(T₂/T₁)
(c) Cp ln (T₁/T₂)
(d) Cv ln (T₂/T₁)
Correct Answer:
2.303 Cp log (T₂/T₁)
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - The element, with atomic number 118, will be
- Be²⁺ is isoelectronic with which of the following ions?
- Which one of the following is not a sulphide ore
- Chlorine is in +1 oxidation state in which of the following
- How many moles of iodine are liberated when 1 mole of potassium dichromate
Topics: Thermodynamics
(179)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The element, with atomic number 118, will be
- Be²⁺ is isoelectronic with which of the following ions?
- Which one of the following is not a sulphide ore
- Chlorine is in +1 oxidation state in which of the following
- How many moles of iodine are liberated when 1 mole of potassium dichromate
Topics: Thermodynamics (179)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply