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How many moles of iodine are liberated when 1 mole of potassium dichromate reacts with potassium iodide
Options
(a) 1
(b) 2
(c) 3
(d) 4
Correct Answer:
3
Explanation:
Iodine is liberated from potassium iodide.
K₂Cr₂O₇ + 4H₂SO₄ → K₂ SO₄+ Cr₂(SO₄)₃ + 4H₂O+ 3[O]
[2KI + H₂SO₄+[O] → K₂ SO₄ + I₂ +H₂O] ⨯ 3 /
[ K₂Cr₂O₇ + 6KI + 7H₂ SO₄ → 4K₂ SO₄+ Cr₂(SO₄)₃ + 7H₂O + 3I₂].
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Topics: Hydrogen and Redox Reactions
(174)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- What is the composition of tear gas
- The set of quantom number for 19th electrons of chromium(Z=24) is
- The number of water molecules is maximum in
- In Dumas’ method of estimation of nitrogen 0.35g of an organic compound gave 55mL
- An organic compound contains 49.3% carbon,6.84% hydrogen and its vapour density
Topics: Hydrogen and Redox Reactions (174)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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