| ⇦ | 
| ⇨ |
How many moles of iodine are liberated when 1 mole of potassium dichromate reacts with potassium iodide
Options
(a) 1
(b) 2
(c) 3
(d) 4
Correct Answer:
3
Explanation:
Iodine is liberated from potassium iodide.
K₂Cr₂O₇ + 4H₂SO₄ → K₂ SO₄+ Cr₂(SO₄)₃ + 4H₂O+ 3[O]
[2KI + H₂SO₄+[O] → K₂ SO₄ + I₂ +H₂O] ⨯ 3 /
[ K₂Cr₂O₇ + 6KI + 7H₂ SO₄ → 4K₂ SO₄+ Cr₂(SO₄)₃ + 7H₂O + 3I₂].
Related Questions: - During the electrolysis of H₂O, volume of H₂ and O₂ are released in the ratio
- Which compound is electron deficient?
- CCl₄ and freons
- If 900 J/g of heat is exchanged at boiling point of water, then what is increase
- The oxide,which can not act as a reducing agent, is
Topics: Hydrogen and Redox Reactions
(174)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- During the electrolysis of H₂O, volume of H₂ and O₂ are released in the ratio
- Which compound is electron deficient?
- CCl₄ and freons
- If 900 J/g of heat is exchanged at boiling point of water, then what is increase
- The oxide,which can not act as a reducing agent, is
Topics: Hydrogen and Redox Reactions (174)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply