| ⇦ |
| ⇨ |
For adiabatic process,which is correct
Options
(a) ΔT = 0
(b) ΔS = 0
(c) q = 0
(d) q(p) = 0
Correct Answer:
q = 0
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - Tincture iodine is
- One would expect proton to have very large
- If an amide is treated with P₂O₅ the likely product is an
- Mass of 0.1 mole of methane is
- In the reaction : 2N₂O₅ → 4NO₂ + O₂, initial pressure is 500 atm and rate
Topics: Thermodynamics
(179)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Tincture iodine is
- One would expect proton to have very large
- If an amide is treated with P₂O₅ the likely product is an
- Mass of 0.1 mole of methane is
- In the reaction : 2N₂O₅ → 4NO₂ + O₂, initial pressure is 500 atm and rate
Topics: Thermodynamics (179)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply