| ⇦ | 
| ⇨ |
In an ac circuit an alternating voltage e = 200 √2 sin 100 t volts is connected to a capacitor of capacity 1 µF. The r.m.s. value of the current in the circuit is
Options
(a) 10 mA
(b) 100 mA
(c) 200 mA
(d) 20 mA
Correct Answer:
20 mA
Explanation:
Vᵣₘₛ = 200 √2 / √2 = 200 V
Iᵣₘₛ = Vᵣₘₛ / Xc = 200/1 / 100 x 10⁻⁶
= 2 x 10⁻² = 20 mA
Related Questions: - The Priniple of LASER action involves
- Two bodies of mass 1 kg and 3 kg have positive vectors i + 2j + k and -3i -2j + k
- Light propagates rectilinearly because of its
- An electron moving in a uniform magnetic field of induction of intensity B,
- Energy stored in the coil of a self inductance 40 mH carrying a steady current of 2A
Topics: Alternating Current
(96)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The Priniple of LASER action involves
- Two bodies of mass 1 kg and 3 kg have positive vectors i + 2j + k and -3i -2j + k
- Light propagates rectilinearly because of its
- An electron moving in a uniform magnetic field of induction of intensity B,
- Energy stored in the coil of a self inductance 40 mH carrying a steady current of 2A
Topics: Alternating Current (96)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
10^-6 is wrong it will be 10*10^-6=10^-5 so correct answer 200mA
V(rms) = 200 √2 / √2 = 200 V
I(rms) = V(rms) / Xc = (200/1) / (100 x 10⁻⁶)
= 2 x 10⁻² = 20 mA