| ⇦ |
| ⇨ |
The displacement of a particle varies according to the relation x=4 (cos π t + sin π t). The amplitude of the particle is
Options
(a) 8
(b) -4
(c) 4
(d) 4 √2
Correct Answer:
4 √2
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - When a ball is thrown up vertically with velocity vₒ,it reaches a maximum height
- The acceleration due to gravity at a place is π² m/sec². Then the time period
- Two springs with spring constants K₁=1500 N/m and K₂=3000 N/m
- The frequency of light ray having the wavelength 3000Å is
- The temperature coefficient of resistance of an alloy used for making resistor is
Topics: Oscillations
(58)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- When a ball is thrown up vertically with velocity vₒ,it reaches a maximum height
- The acceleration due to gravity at a place is π² m/sec². Then the time period
- Two springs with spring constants K₁=1500 N/m and K₂=3000 N/m
- The frequency of light ray having the wavelength 3000Å is
- The temperature coefficient of resistance of an alloy used for making resistor is
Topics: Oscillations (58)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply