| ⇦ | 
| ⇨ |
In a parallel plate capacitor with plate area A and charge Q, the force on one plate because of the charge on the other is equal to
Options
(a) Q²/ε₀A²
(b) Q²/2ε₀A²
(c) Q²/ε₀A
(d) Q²/2ε₀A
Correct Answer:
Q²/2ε₀A
Explanation:
Force between the plates of a parallel plate capacitor |F| = V²A / 2ε₀ = Q² / 2ε₀A
Related Questions: - The magnifying power of a telescope is 9. When it is adjusted for parallel rays
- If R is the radius of earth, the height at which the weight of a body 1/4 of its weight
- If a spring of spring constant k stretched by a length x under tension T, the energy
- Given the value of Rydberg constant is 10⁷ m⁻¹, the wave number of the last line
- Heat produced in a resistance according to which law?
Topics: Electrostatics
(146)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The magnifying power of a telescope is 9. When it is adjusted for parallel rays
- If R is the radius of earth, the height at which the weight of a body 1/4 of its weight
- If a spring of spring constant k stretched by a length x under tension T, the energy
- Given the value of Rydberg constant is 10⁷ m⁻¹, the wave number of the last line
- Heat produced in a resistance according to which law?
Topics: Electrostatics (146)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply