| ⇦ | 
| ⇨ |
Given the value of Rydberg constant is 10⁷ m⁻¹, the wave number of the last line of the Balmer series in hydrogen spectrum will be
Options
(a) 0.5×10⁷ m⁻¹
(b) 0.25×10⁷ m⁻¹
(c) 2.5×10⁷ m⁻¹
(d) 0.025×10⁷ m⁻¹
Correct Answer:
0.25×10⁷ m⁻¹
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - If two vectors are equal in magnitude and their resultant is also equal in magnitude
- In Young’s double slit experiment, for which colour the fringe width is the least
- X-ray beam can be deflected by
- A sound source is moving towards a stationary listener with 1/10th of the speed
- If a small sphere is let fall vertically in a large quantity of still liquid of density
Topics: Atoms and Nuclei
(136)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- If two vectors are equal in magnitude and their resultant is also equal in magnitude
- In Young’s double slit experiment, for which colour the fringe width is the least
- X-ray beam can be deflected by
- A sound source is moving towards a stationary listener with 1/10th of the speed
- If a small sphere is let fall vertically in a large quantity of still liquid of density
Topics: Atoms and Nuclei (136)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply