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If v is the speed of sound in air, then the shortest length of the closed pipe which resonates to a frequency n
Options
(a) v / 4n
(b) v / 2n
(c) 2n / v
(d) 4n / v
Correct Answer:
v / 4n
Explanation:
For closed pipe, l = λ/4 in fundamental mode when the length is shortest.
v = nλ ⇒ v = n × 4l ⇒ l = v/4n
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Topics: Waves
(80)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A bar magnet of magnetic moment M is placed at right angles to a magnetic
- A cricketer catches a ball of mass 150 g in 0.1 sec moving with speed 20 m/s
- A concave mirror of focal length f₁ is placed at a distance d from a convex lens
- The escape velocity of a body on an imaginary planet which is thrice the radius
- Hard X-rays for the study of fractures in bones should have a minimum wavelength
Topics: Waves (80)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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