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If v is the speed of sound in air, then the shortest length of the closed pipe which resonates to a frequency n
Options
(a) v / 4n
(b) v / 2n
(c) 2n / v
(d) 4n / v
Correct Answer:
v / 4n
Explanation:
For closed pipe, l = λ/4 in fundamental mode when the length is shortest.
v = nλ ⇒ v = n × 4l ⇒ l = v/4n
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Topics: Waves
(80)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Energy stored in the coil of a self inductance 40 mH carrying a steady current of 2A
- An ideal gas is expanding such that PT²=constant. The coefficient of volume
- The numebr 0 (zero) is required for
- A source of unknown frequency gives 4 beats/s, when sounded with a source harmonic
- Two vessels separately contain two ideal gases A and B at the same temperature,
Topics: Waves (80)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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