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If v is the speed of sound in air, then the shortest length of the closed pipe which resonates to a frequency n
Options
(a) v / 4n
(b) v / 2n
(c) 2n / v
(d) 4n / v
Correct Answer:
v / 4n
Explanation:
For closed pipe, l = λ/4 in fundamental mode when the length is shortest.
v = nλ ⇒ v = n × 4l ⇒ l = v/4n
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Topics: Waves
(80)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A conveyor belt is moving at a constant speed of 2 m/s. A box is gently dropped on it
- When 1 kg of ice at 0⁰C melts to water at 0⁰C, the resulting change in its entropy
- The moon’s radius is 1/ 4 that of the earth and its mass is 1 / 80 times that of the earth
- The maximum and minimum intensities of two sources is 4:1. The ratio of amplitude is
- A wire mesh consisting of very small squares is viewed at a distance
Topics: Waves (80)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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