| ⇦ | 
| ⇨ |
If v is the speed of sound in air, then the shortest length of the closed pipe which resonates to a frequency n
Options
(a) v / 4n
(b) v / 2n
(c) 2n / v
(d) 4n / v
Correct Answer:
v / 4n
Explanation:
For closed pipe, l = λ/4 in fundamental mode when the length is shortest.
v = nλ ⇒ v = n × 4l ⇒ l = v/4n
Related Questions: - A deutron is bombarded on ₈O¹⁶ nucleus and α-particle is emitted. The product nucleus is
- The condition under which a microwave oven heats up a food item containing
- If a small sphere is let fall vertically in a large quantity of still liquid of density
- In an a.c circuit the e.m.f. (e) and the current (i) at any instant are given
- A comb run through one’s dry hair attracts small bits of paper. This is due to
Topics: Waves
(80)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A deutron is bombarded on ₈O¹⁶ nucleus and α-particle is emitted. The product nucleus is
- The condition under which a microwave oven heats up a food item containing
- If a small sphere is let fall vertically in a large quantity of still liquid of density
- In an a.c circuit the e.m.f. (e) and the current (i) at any instant are given
- A comb run through one’s dry hair attracts small bits of paper. This is due to
Topics: Waves (80)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply