| ⇦ | 
| ⇨ |
If v is the speed of sound in air, then the shortest length of the closed pipe which resonates to a frequency n
Options
(a) v / 4n
(b) v / 2n
(c) 2n / v
(d) 4n / v
Correct Answer:
v / 4n
Explanation:
For closed pipe, l = λ/4 in fundamental mode when the length is shortest.
v = nλ ⇒ v = n × 4l ⇒ l = v/4n
Related Questions: - A proton beam enters a magnetic field of 10⁻⁴ Wb/m² normally. If the specific charge
- If 75% of the radioactive reaction is completed in 2 hrs, what would be
- 1 Wb/m² equal to
- A nucleus of mass number 220, initially at rest, emits an α-particle. If the Q-value
- The velocity of electromagnetic radiation in a medium of permittivity ε₀
Topics: Waves
(80)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A proton beam enters a magnetic field of 10⁻⁴ Wb/m² normally. If the specific charge
- If 75% of the radioactive reaction is completed in 2 hrs, what would be
- 1 Wb/m² equal to
- A nucleus of mass number 220, initially at rest, emits an α-particle. If the Q-value
- The velocity of electromagnetic radiation in a medium of permittivity ε₀
Topics: Waves (80)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply