| ⇦ | 
| ⇨ |
If uncertainty in position and momentum are equal, then uncertainty in velocity is :
Options
(a) 1/2m x √(h/π)
(b) √(h/2π)
(c) 1/m x √(h/π)
(d) √(h/π)
Correct Answer:
1/2m x √(h/π)
Explanation:
We known Δp.Δx ≥ h / 4π
or m.Δv.Δx = h / 4π [ .·. Δp = mΔV]
since Δp = Δx (given)
.·. Δp.Δp = h / 4π or mΔv = h / 4π
or (Δv)² = h / 4πm²
or Δv = √ h / 4πm² = 1 / 2 m √ h / π..
Related Questions: - Correct relation between dissociation constant of a dibasic acid is
- The use of chemical for treatment of diseases are called as
- The electron was shown experimentally to have wave properties by
- Calcium is obtained by the
- Which one of the following is employed as a tranquilizer
Question Type: Memory
(964)
Difficulty Level: Easy
(1008)
Topics: Structure of Atom
(90)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Correct relation between dissociation constant of a dibasic acid is
- The use of chemical for treatment of diseases are called as
- The electron was shown experimentally to have wave properties by
- Calcium is obtained by the
- Which one of the following is employed as a tranquilizer
Question Type: Memory (964)
Difficulty Level: Easy (1008)
Topics: Structure of Atom (90)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
We Know that, Δx.Δp ≥ h/4π,
∵ x = p
we can find answer with using two formulae,
first- Δx.Δp ≥ h/4π,
second- Δx.Δv ≥ h/4mπ.
Here, Δx = Δp = y
According to Heisenberg’s uncertainty principle
Δx*Δp = h/4π
y² = h/4π
y = √h/√4π
y = 1/2 √h/√π
So p(Momentum) = 1/2 √h/√π = mΔv
1/2 √h/√π = mΔv
1/2m √h/√π = Δv
So ans is….. Δv = 1/2m √h/√π