| ⇦ | 
| ⇨ |
Vapour pressure of dilute aqueous solution of glucose is 750 mm of mercury at 373K. The mole fraction of solute is
Options
(a) 1/76
(b) 1/7.6
(c) 1/38
(d) 1/0.1
Correct Answer:
1/76
Explanation:
p(s) = p⁰(1 – x₂).
⇒ 750 = 760(1 – x₂) or 750/760 = 1 – x₂, or 750/760 -1 = -x₂
⇒ x₂ = 1/76.
Related Questions: - Acidity of diprotic acids in aqueous solutions increases in the order
- In hydrogen atom, energy of first excited state is –3.4 eV. Find out KE
- The equilibrium constant of a reaction is 300. If the volume of a reaction flask
- Which of the following shows maximum number of oxidation states
- In an exothermic reaction(reversible) which of the following has positive value
Topics: Solid State and Solutions
(91)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Acidity of diprotic acids in aqueous solutions increases in the order
- In hydrogen atom, energy of first excited state is –3.4 eV. Find out KE
- The equilibrium constant of a reaction is 300. If the volume of a reaction flask
- Which of the following shows maximum number of oxidation states
- In an exothermic reaction(reversible) which of the following has positive value
Topics: Solid State and Solutions (91)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply