| ⇦ | 
| ⇨ |
Which one of the following transition metals ions shows magnetic moment of 5.92 BM
Options
(a) Mn²⁺
(b) Ti³⁺
(c) Cr³⁺
(d) Cu²⁺
Correct Answer:
Mn²⁺
Explanation:
Magnetic moment = √n(n+2) = 5.92. i.e., n = 5 . Number of unpaired electron in Mn²⁺ = 5. Number of unpaired electron in Ti³⁺ = 1. Number of unpaired electron in Cr³⁺ = 3. Number of unpaired electron in Cu²⁺ = 1. Number of unpaired electrons in Co²⁺ = 3. Thus Mn²⁺ have magnetic moment = 5.92 BM.
Related Questions: - Which would exhibit ionisation isomerism
- A mixture containing benzene and chlorobenzene is seperated by
- Dumas method is used for the estimation of
- Zeolite used to soften hardness of water is, hydrated
- How many FeSO₄.7H₂SO₄ will be oxidised by an acidified solution containing 9.48g
Topics: Coordination Compounds
(87)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Which would exhibit ionisation isomerism
- A mixture containing benzene and chlorobenzene is seperated by
- Dumas method is used for the estimation of
- Zeolite used to soften hardness of water is, hydrated
- How many FeSO₄.7H₂SO₄ will be oxidised by an acidified solution containing 9.48g
Topics: Coordination Compounds (87)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply