| ⇦ | 
| ⇨ |
If the ratio of the rates of diffusion of two gases A and B is 4 : 1. Then the ratio of their densities in the same order is
Options
(a) 16 : 1
(b) 4 : 1
(c) 1 : 4
(d) 1 : 16
Correct Answer:
1 : 16
Explanation:
Rate of diffusion ∝ 1 / √d. rA / rB = √dB / dA ⇒ 4 / 1 = √dB / dA ⇒ 16 / 1 = dB / dA ⇒ dA / dB = 1 / 16.
Related Questions: - Which one of the following forms with an excess of CN⁻ (cyanide) a complex
- Cyclopentadienyl anion is
- The density of air is 0.001293 g/cc at STP. Its vapour density is
- The compound containing coordinate bond is
- A physician wishes to prepare a buffer solution at pH = 3.85
Topics: States of Matter Gases and Liquids
(80)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Which one of the following forms with an excess of CN⁻ (cyanide) a complex
- Cyclopentadienyl anion is
- The density of air is 0.001293 g/cc at STP. Its vapour density is
- The compound containing coordinate bond is
- A physician wishes to prepare a buffer solution at pH = 3.85
Topics: States of Matter Gases and Liquids (80)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
According to Graham’s law of diffusion,
RA/RB=√dB/dA
or,(4/1)2=dB/dA
or,16/1=dB/dA
or,dA:dB= 1:16