| ⇦ | 
| ⇨ |
If the ratio of the rates of diffusion of two gases A and B is 4 : 1. Then the ratio of their densities in the same order is
Options
(a) 16 : 1
(b) 4 : 1
(c) 1 : 4
(d) 1 : 16
Correct Answer:
1 : 16
Explanation:
Rate of diffusion ∝ 1 / √d. rA / rB = √dB / dA ⇒ 4 / 1 = √dB / dA ⇒ 16 / 1 = dB / dA ⇒ dA / dB = 1 / 16.
Related Questions: - In the softening of the water by passing it through cationic and anionic exchang
- What products are formed when the following compound is treated with Br₂
- The metal used to recover copper from a solution of copper sulphate is
- Numbers of moles of K₂Cr₂O₇ reduced by one mole os Sn²⁺
- Which of the following will not undergo Hell-Volhard-Zelinsky reaction
Topics: States of Matter Gases and Liquids
(80)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- In the softening of the water by passing it through cationic and anionic exchang
- What products are formed when the following compound is treated with Br₂
- The metal used to recover copper from a solution of copper sulphate is
- Numbers of moles of K₂Cr₂O₇ reduced by one mole os Sn²⁺
- Which of the following will not undergo Hell-Volhard-Zelinsky reaction
Topics: States of Matter Gases and Liquids (80)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
According to Graham’s law of diffusion,
RA/RB=√dB/dA
or,(4/1)2=dB/dA
or,16/1=dB/dA
or,dA:dB= 1:16