| ⇦ | 
| ⇨ |
If the radius of star is R and it acts as a black body, what would be the temperature of the star, in which the rate of energy protection is Q?
Options
(a) Q / 4 πR²σ
(b) (Q / 4 πR²σ)⁻¹/²
(c) (4 πR²Q / σ)¹/⁴
(d) (Q / 4 πR²σ)¹/⁴
Correct Answer:
(Q / 4 πR²σ)¹/⁴
Explanation:
Stefan’s law for black body radiation Q = σe AT⁴
T = [Q / σ(4πR²) ]¹/⁴ Here e= 1
A = 4πR²
Related Questions: - A uniform force of (3i+j) Nacts on a particle of mass 2 kg.Hence the particle is displaced
- The phase difference between the instantaneous velocity and acceleration of a particle
- A bus is moving with a velocity of 5 ms⁻¹ towards a huge wall.
- The purpose of using heavy water in nuclear reactor is
- A freely suspended bar magnet aligns itself in
Topics: Properties of Bulk Matter
(130)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A uniform force of (3i+j) Nacts on a particle of mass 2 kg.Hence the particle is displaced
- The phase difference between the instantaneous velocity and acceleration of a particle
- A bus is moving with a velocity of 5 ms⁻¹ towards a huge wall.
- The purpose of using heavy water in nuclear reactor is
- A freely suspended bar magnet aligns itself in
Topics: Properties of Bulk Matter (130)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply