| ⇦ | 
| ⇨ |
If the radius of star is R and it acts as a black body, what would be the temperature of the star, in which the rate of energy protection is Q?
Options
(a) Q / 4 πR²σ
(b) (Q / 4 πR²σ)⁻¹/²
(c) (4 πR²Q / σ)¹/⁴
(d) (Q / 4 πR²σ)¹/⁴
Correct Answer:
(Q / 4 πR²σ)¹/⁴
Explanation:
Stefan’s law for black body radiation Q = σe AT⁴
T = [Q / σ(4πR²) ]¹/⁴ Here e= 1
A = 4πR²
Related Questions: - Maximum kinetic energy of electrons emitted in photoelectric effect increases when
- In the given figure, a diode D is connected to an external resistance R=100 Ω
- The particle executing simple harmonic motion has a kinetic energy K₀cos²ωt.
- In an ac circuit an alternating voltage e = 200 √2 sin 100 t volts is connected
- A cell of emf E and internal resistance r supplies current for the same time
Topics: Properties of Bulk Matter
(130)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Maximum kinetic energy of electrons emitted in photoelectric effect increases when
- In the given figure, a diode D is connected to an external resistance R=100 Ω
- The particle executing simple harmonic motion has a kinetic energy K₀cos²ωt.
- In an ac circuit an alternating voltage e = 200 √2 sin 100 t volts is connected
- A cell of emf E and internal resistance r supplies current for the same time
Topics: Properties of Bulk Matter (130)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply