| ⇦ | 
| ⇨ |
If the radius of star is R and it acts as a black body, what would be the temperature of the star, in which the rate of energy protection is Q?
Options
(a) Q / 4 πR²σ
(b) (Q / 4 πR²σ)⁻¹/²
(c) (4 πR²Q / σ)¹/⁴
(d) (Q / 4 πR²σ)¹/⁴
Correct Answer:
(Q / 4 πR²σ)¹/⁴
Explanation:
Stefan’s law for black body radiation Q = σe AT⁴
T = [Q / σ(4πR²) ]¹/⁴ Here e= 1
A = 4πR²
Related Questions: - The ratio of the weight of a man in a stationary lift and when it is moving downwards
- A milli ammeter of range 10 mA has a coil of resistance 1 ohm
- In R-L-C series circuit, the potential differences across each element is 20 V.
- In a uniform circular motion, work done in one complete rotation is
- A solid cylinder of mass M and radius R rolls without slipping down and inclined plane
Topics: Properties of Bulk Matter
(130)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The ratio of the weight of a man in a stationary lift and when it is moving downwards
- A milli ammeter of range 10 mA has a coil of resistance 1 ohm
- In R-L-C series circuit, the potential differences across each element is 20 V.
- In a uniform circular motion, work done in one complete rotation is
- A solid cylinder of mass M and radius R rolls without slipping down and inclined plane
Topics: Properties of Bulk Matter (130)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply