| ⇦ | 
| ⇨ |
If the radius of star is R and it acts as a black body, what would be the temperature of the star, in which the rate of energy protection is Q?
Options
(a) Q / 4 πR²σ
(b) (Q / 4 πR²σ)⁻¹/²
(c) (4 πR²Q / σ)¹/⁴
(d) (Q / 4 πR²σ)¹/⁴
Correct Answer:
(Q / 4 πR²σ)¹/⁴
Explanation:
Stefan’s law for black body radiation Q = σe AT⁴
T = [Q / σ(4πR²) ]¹/⁴ Here e= 1
A = 4πR²
Related Questions: - A stone is tied to a string of length l and whirled in a vertical circle with the other end
- A hollow sphere of radius 0.1m has a charge of 5×10⁻⁸C. The potential
- Radii of curvature of a converging lens are in the rato 1:2. Its focal length
- A particle starting from the origin (0, 0) moves in a straight line in the (x, y) plane
- If two electric bulbs have 40 W and 60 W ratings at 220 V, then the ratio
Topics: Properties of Bulk Matter
(130)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A stone is tied to a string of length l and whirled in a vertical circle with the other end
- A hollow sphere of radius 0.1m has a charge of 5×10⁻⁸C. The potential
- Radii of curvature of a converging lens are in the rato 1:2. Its focal length
- A particle starting from the origin (0, 0) moves in a straight line in the (x, y) plane
- If two electric bulbs have 40 W and 60 W ratings at 220 V, then the ratio
Topics: Properties of Bulk Matter (130)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply