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If the radius of star is R and it acts as a black body, what would be the temperature of the star, in which the rate of energy protection is Q?
Options
(a) Q / 4 πR²σ
(b) (Q / 4 πR²σ)⁻¹/²
(c) (4 πR²Q / σ)¹/⁴
(d) (Q / 4 πR²σ)¹/⁴
Correct Answer:
(Q / 4 πR²σ)¹/⁴
Explanation:
Stefan’s law for black body radiation Q = σe AT⁴
T = [Q / σ(4πR²) ]¹/⁴ Here e= 1
A = 4πR²
Related Questions: - A wire having resistance 12Ω is bent in the form of an equilateral triangle.
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Topics: Properties of Bulk Matter
(130)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A wire having resistance 12Ω is bent in the form of an equilateral triangle.
- As per Bohr model, the minimum energy (in eV) required to remove an electron
- The ratio of the acceleration for a solid sphere(mass m and radius R)rolling down
- A gas is suddenly expanded such that its final volume becomes 3 times
- A radioactive substance decays to 1/16th of its initial activity in 40 days.
Topics: Properties of Bulk Matter (130)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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