⇦ | ⇨ |
If the radius of star is R and it acts as a black body, what would be the temperature of the star, in which the rate of energy protection is Q?
Options
(a) Q / 4 πR²σ
(b) (Q / 4 πR²σ)⁻¹/²
(c) (4 πR²Q / σ)¹/⁴
(d) (Q / 4 πR²σ)¹/⁴
Correct Answer:
(Q / 4 πR²σ)¹/⁴
Explanation:
Stefan’s law for black body radiation Q = σe AT⁴
T = [Q / σ(4πR²) ]¹/⁴ Here e= 1
A = 4πR²
Related Questions: - If a body is rolling on the surface, its total energy will be
- A coil of resistance 20 ohm and inductance 5H is connected with a 100V battery
- If in a p-n junction, a square input signal of 10 V is applied as shown, then the output
- A freely suspended bar magnet aligns itself in
- A vibration magnetometer placed in magnetic meridian has a small bar magnet
Topics: Properties of Bulk Matter
(130)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- If a body is rolling on the surface, its total energy will be
- A coil of resistance 20 ohm and inductance 5H is connected with a 100V battery
- If in a p-n junction, a square input signal of 10 V is applied as shown, then the output
- A freely suspended bar magnet aligns itself in
- A vibration magnetometer placed in magnetic meridian has a small bar magnet
Topics: Properties of Bulk Matter (130)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply