| ⇦ |
| ⇨ |
If the pressure of gas is increased from 1.01×10⁵ Pa to 1.165×10⁵ Pa and volume is decreases by 10% at constant temperature then the bulk modulus of the gas is
Options
(a) 15.5×10⁵ Pa
(b) 1.4×10⁵ Pa
(c) 1.55×10⁵ Pa
(d) 0.0155×10⁵ Pa
Correct Answer:
1.55×10⁵ Pa
Explanation:
Bulk modulus = normal stress / volumetric strain
= (F/A) / (-∆V/V) = -(PV / ∆V)
For an isothermal process, PV = constant
So, PdV + VdP = 0 ⇒ (-VdP / dV) = P
B = (-VdP / dV) = (100 / 10) × (1.165 × 10⁵ – 1.01 × 10⁵)
= 1.55 × 10⁵ Pa.
Related Questions: - Wb/m² is equal to
- A rod of 10 cm length is moving perpendicular to uniform magntic field of intensity
- What is the difference between soft and hard X-ray?
- Two particles of masses m₁ m₂ move with initial velocities u₁ and u₂
- If both the resistance and the inductance in an LR AC series circuit are doubled
Topics: Thermodynamics
(179)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Wb/m² is equal to
- A rod of 10 cm length is moving perpendicular to uniform magntic field of intensity
- What is the difference between soft and hard X-ray?
- Two particles of masses m₁ m₂ move with initial velocities u₁ and u₂
- If both the resistance and the inductance in an LR AC series circuit are doubled
Topics: Thermodynamics (179)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply