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A rod of 10 cm length is moving perpendicular to uniform magntic field of intensity 5×10⁻⁴Wbm⁻². If the acceleration of the rod is 5ms⁻¹, then the rate of increase of induced emf is
Options
(a) 25×10⁻⁴ Vs⁻¹
(b) 2.5×10⁻⁴ Vs⁻¹
(c) 2.0×10⁻⁴ Vs⁻¹
(d) 20×10⁻⁴ Vs⁻¹
Correct Answer:
2.5×10⁻⁴ Vs⁻¹
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - A linear aperture whose width is 0.02 cm is placed immediately in front of a lens
- A charged oil drop is suspended in a uniform field at 3×10⁴ V/m so that it neither falls
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Topics: Electromagnetic Induction
(76)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A linear aperture whose width is 0.02 cm is placed immediately in front of a lens
- A charged oil drop is suspended in a uniform field at 3×10⁴ V/m so that it neither falls
- Which of the following is an example of ideal black body?
- If the wavelength of light in vacuum be, the wavelength in a medium of refractive index
- The ratio of minimum wavelengths of Lyman and Balmer series will be
Topics: Electromagnetic Induction (76)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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