IF the bond energies of H – H , Br – Br and H – Br are 433 , 192 and 364 kJ mol⁻¹

⇦

⇨

IF the bond energies of H – H , Br – Br and H – Br are 433 , 192 and 364 kJ mol⁻¹ respectively, the ΔH° for the reaction
H₂(g) + Br₂(g) → 2HBr(g) is

Options

(a) -261 kJ
(b) ⁺103 kJ
(c) ⁺261 kJ
(d) -103 kJ

Correct Answer:

-103 kJ

Explanation:

H – H + Br – Br → 2H – Br,
(433) + (192) (2 x 364)
=625 =728
(Energyabsorbed) (Energy released)
Net energy released = 728 – 625 = 103 KJ. i.e. ΔH = -103 KJ.

Related Questions:

1. How many coulombs of electricity are required for the reduction of 1 mol
2. In Duma’s method for estimation of nitrogen, 0.25g of an organic compound
3. Oxidation numbers of P in PO₄³⁻, of S in SO₄²⁻ and that of Cr in Cr₂O₇²⁻
4. The constituents of porland cement are
5. Glycerine is purified by

Topics: Thermodynamics (179)
Subject: Chemistry (2512)

---

Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score

18000+ students are using NEETLab to improve their score. What about you?

Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.

---

Share this page with your friends