⇦ | ⇨ |
The work done during the expansion of a gas from a volume of 4 dm³ to 6 dm³ against a constant external pressure of 3 atm is (1atm = 101.32 J)
Options
(a) -6 J
(b) -608 J
(c) ⁺304 J
(d) -304 J
Correct Answer:
-608 J
Explanation:
Work = -P(ext) x volume change =
-3 x 101.32 x (6 – 4)
= -6 x 101.32 = -607.92 J = -608 J
Related Questions: - Ethyl alcohol gives ethyl chloride with the help of
- Chronic chloroform exposure may cause damage to liver and kidney, due to the
- Which would exhibit ionisation isomerism
- The wrong statements about glycerol is
- Change in enthalpy for reaction,2H₂O₂ → 2H₂O + O₂
Topics: Thermodynamics
(179)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Ethyl alcohol gives ethyl chloride with the help of
- Chronic chloroform exposure may cause damage to liver and kidney, due to the
- Which would exhibit ionisation isomerism
- The wrong statements about glycerol is
- Change in enthalpy for reaction,2H₂O₂ → 2H₂O + O₂
Topics: Thermodynamics (179)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply