| ⇦ | 
| ⇨ |
IF the bond energies of H – H , Br – Br and H – Br are 433 , 192 and 364 kJ mol⁻¹ respectively, the ΔH° for the reaction
H₂(g) + Br₂(g) → 2HBr(g) is
Options
(a) -261 kJ
(b) ⁺103 kJ
(c) ⁺261 kJ
(d) -103 kJ
Correct Answer:
-103 kJ
Explanation:
H – H + Br – Br → 2H – Br,
(433) + (192) (2 x 364)
=625 =728
(Energyabsorbed) (Energy released)
Net energy released = 728 – 625 = 103 KJ. i.e. ΔH = -103 KJ.
Related Questions: - If the gas at constant temperature and pressure expands, then its
- The oxidation of benzene by V₂O₅ in the presence of air produces
- Which of the following is a chiral compound
- Considering the state of hybridization of carbon atoms, find out the molecule
- Unpleasent smelling carbylamines are formed by heating alkali and chloroform with
Topics: Thermodynamics
(179)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- If the gas at constant temperature and pressure expands, then its
- The oxidation of benzene by V₂O₅ in the presence of air produces
- Which of the following is a chiral compound
- Considering the state of hybridization of carbon atoms, find out the molecule
- Unpleasent smelling carbylamines are formed by heating alkali and chloroform with
Topics: Thermodynamics (179)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply