Decreasing order of stability of O₂ , O₂⁻ , O₂⁺ and O₂²⁻ is

Decreasing Order Of Stability Of O O O Chemistry Question

Decreasing order of stability of O₂ , O₂⁻ , O₂⁺ and O₂²⁻ is

Options

(a) O₂²⁻ > O₂⁻ > O₂ >O₂⁺
(b) O₂> O₂⁺ > O₂²⁻ > O₂⁻
(c) O₂⁻ > O₂²⁻ > O₂⁺ >O₂
(d) O₂⁺ > O₂ > O₂⁻ > O₂²⁻

Correct Answer:

O₂⁺ > O₂ > O₂⁻ > O₂²⁻

Explanation:

According to molecular orbital theory as bond order decreases stability of the molecule decreases
Bond order =1/2 (N(b)-N(a))
Bond order for O₂⁺=1/2 (10-5)=2.5
Bond order for O₂=1/2 (10-6)=2
Bond order for O₂⁻=1/2 (10-7)=1.5
Bond order for O₂²⁻=1/2 (10-8)=1.0
hence the correct order is
O₂⁺ > O₂ > O₂⁻> O₂²⁻

Related Questions:

  1. The basic component of photochemical smog is
  2. For the reaction C(s) + O₂(g)
  3. On the extraction of iron, the slag produced is
  4. The products of the following reaction are
  5. The oxidation of benzene by V₂O₅ in the presence of air produces

Topics: Chemical Bonding and Molecular Structure (86)
Subject: Chemistry (2512)

Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score

18000+ students are using NEETLab to improve their score. What about you?

Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.

NEETLab Mobile App

Share this page with your friends

Be the first to comment

Leave a Reply

Your email address will not be published.


*