If the binding energy of the nucleon in ₃⁷Li and ₂⁴He nuclei are 5.60 MeV and 7.06 MeV

If The Binding Energy Of The Nucleon In Li And Physics Question

If the binding energy of the nucleon in ₃⁷Li and ₂⁴He nuclei are 5.60 MeV and 7.06 MeV respectively, then in the reaction: p+₃⁷Li→2 ₂⁴He, energy of proton must be

Options

(a) 39.2 MeV
(b) 28.24 MeV
(c) 17.28 MeV
(d) 1.46 MeV

Correct Answer:

17.28 MeV

Explanation:

No explanation available. Be the first to write the explanation for this question by commenting below.

Related Questions:

  1. P-type semiconductors are made by adding impurity element
  2. A person wants a real image of his own, 3 times enlarged. Where should he stand
  3. A ballon rises from rest with a constant acceleration g/8. A stone is released
  4. Charge Q is divided into two parts which are then kept some distance apart. The force
  5. The horizontal range and the maximum height of a projectile are equal

Topics: Atoms and Nuclei (136)
Subject: Physics (2479)

Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score

18000+ students are using NEETLab to improve their score. What about you?

Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.

NEETLab Mobile App

Share this page with your friends

Be the first to comment

Leave a Reply

Your email address will not be published.


*