| ⇦ | 
| ⇨ |
If the binding energy of the nucleon in ₃⁷Li and ₂⁴He nuclei are 5.60 MeV and 7.06 MeV respectively, then in the reaction: p+₃⁷Li→2 ₂⁴He, energy of proton must be
Options
(a) 39.2 MeV
(b) 28.24 MeV
(c) 17.28 MeV
(d) 1.46 MeV
Correct Answer:
17.28 MeV
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - A particle moves with constant speed v along a circular path of radius r and completes
- Photoelectric current from a given photocell will depend upon
- Wavefront is the locus of all points, where the particles of the medium
- We get Balmer series when electron comes from
- The valence band and the conductance band of a solid overlap at low temperature
Topics: Atoms and Nuclei
(136)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A particle moves with constant speed v along a circular path of radius r and completes
- Photoelectric current from a given photocell will depend upon
- Wavefront is the locus of all points, where the particles of the medium
- We get Balmer series when electron comes from
- The valence band and the conductance band of a solid overlap at low temperature
Topics: Atoms and Nuclei (136)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply