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If the binding energy of the nucleon in ₃⁷Li and ₂⁴He nuclei are 5.60 MeV and 7.06 MeV respectively, then in the reaction: p+₃⁷Li→2 ₂⁴He, energy of proton must be
Options
(a) 39.2 MeV
(b) 28.24 MeV
(c) 17.28 MeV
(d) 1.46 MeV
Correct Answer:
17.28 MeV
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
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Topics: Atoms and Nuclei
(136)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The drive shaft of an automobile rotates at 3600 rpm and transmits 80 HP
- If the lattice parameter for a crystalline structure is 3.6 Å, then the atomic radius
- Equal currents are passing through two very long and straight parallel wires
- A small object of uniform density rolls up a curved surface with an initial velocity
- The energy of a hydrogen atom in the ground state is – 13.6 eV. The energy of a He⁺ ion
Topics: Atoms and Nuclei (136)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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