| ⇦ | 
| ⇨ |
If the binding energy of the nucleon in ₃⁷Li and ₂⁴He nuclei are 5.60 MeV and 7.06 MeV respectively, then in the reaction: p+₃⁷Li→2 ₂⁴He, energy of proton must be
Options
(a) 39.2 MeV
(b) 28.24 MeV
(c) 17.28 MeV
(d) 1.46 MeV
Correct Answer:
17.28 MeV
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - The de-Broglie wavelength of an electron having 80 eV of energy is nearly
- The coefficient of friction between the tyres and the road is 0.25. The maximum speed
- The unit of permitivity of free space, ε₀ is
- The point of suspension λ of a simple pendulum with normal time period T₁ is moving
- If force(F), Velocity(V) and time(T) are taken as fundamental units, then the dimensions
Topics: Atoms and Nuclei
(136)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The de-Broglie wavelength of an electron having 80 eV of energy is nearly
- The coefficient of friction between the tyres and the road is 0.25. The maximum speed
- The unit of permitivity of free space, ε₀ is
- The point of suspension λ of a simple pendulum with normal time period T₁ is moving
- If force(F), Velocity(V) and time(T) are taken as fundamental units, then the dimensions
Topics: Atoms and Nuclei (136)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply