| ⇦ | 
| ⇨ |
If the binding energy of the nucleon in ₃⁷Li and ₂⁴He nuclei are 5.60 MeV and 7.06 MeV respectively, then in the reaction: p+₃⁷Li→2 ₂⁴He, energy of proton must be
Options
(a) 39.2 MeV
(b) 28.24 MeV
(c) 17.28 MeV
(d) 1.46 MeV
Correct Answer:
17.28 MeV
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - A 50Hz AC signal is applied in a circuit of inductance of (1/π)H and resistance 2100Ω
- The number of significant figures in 0.06900
- A heavy nucleus at rest breaks into two fragments which fly off with velocities
- Rate of photoelectric emission is proportional to
- As a result of interference of two coherent sources of light, energy is
Topics: Atoms and Nuclei
(136)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A 50Hz AC signal is applied in a circuit of inductance of (1/π)H and resistance 2100Ω
- The number of significant figures in 0.06900
- A heavy nucleus at rest breaks into two fragments which fly off with velocities
- Rate of photoelectric emission is proportional to
- As a result of interference of two coherent sources of light, energy is
Topics: Atoms and Nuclei (136)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply