| ⇦ | 
| ⇨ |
If the binding energy of the nucleon in ₃⁷Li and ₂⁴He nuclei are 5.60 MeV and 7.06 MeV respectively, then in the reaction: p+₃⁷Li→2 ₂⁴He, energy of proton must be
Options
(a) 39.2 MeV
(b) 28.24 MeV
(c) 17.28 MeV
(d) 1.46 MeV
Correct Answer:
17.28 MeV
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - The phase difference between the instantaneous velocity and acceleration of a particle
- Diameter of the objective of a telescope is 200 cm. What is the resolving power
- If ∆Q>0 when heat flows into a system, ∆W>0 when work is done on the system
- A solid sylinder of mass 3 kg is rolling on a horizontal surface with velocity 4 ms⁻¹
- The temperature of a metal block is increased from 27⁰C to 84⁰C. The rate of radiated energy
Topics: Atoms and Nuclei
(136)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The phase difference between the instantaneous velocity and acceleration of a particle
- Diameter of the objective of a telescope is 200 cm. What is the resolving power
- If ∆Q>0 when heat flows into a system, ∆W>0 when work is done on the system
- A solid sylinder of mass 3 kg is rolling on a horizontal surface with velocity 4 ms⁻¹
- The temperature of a metal block is increased from 27⁰C to 84⁰C. The rate of radiated energy
Topics: Atoms and Nuclei (136)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply