| ⇦ | 
| ⇨ |
If the binding energy of the nucleon in ₃⁷Li and ₂⁴He nuclei are 5.60 MeV and 7.06 MeV respectively, then in the reaction: p+₃⁷Li→2 ₂⁴He, energy of proton must be
Options
(a) 39.2 MeV
(b) 28.24 MeV
(c) 17.28 MeV
(d) 1.46 MeV
Correct Answer:
17.28 MeV
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - Two concentric spheres kept in air have radii R and r.
- A solid sylinder of mass 3 kg is rolling on a horizontal surface with velocity 4 ms⁻¹
- A motor-cyclist drives a motor cycle in a vertical circle. His minimum velocity
- In the half wave rectifier circuit operating from 50 Hz mains frequency,
- An electron in a circular orbit of radius 0.05 nm performs 10¹⁶ rev/s. The magnetic
Topics: Atoms and Nuclei
(136)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Two concentric spheres kept in air have radii R and r.
- A solid sylinder of mass 3 kg is rolling on a horizontal surface with velocity 4 ms⁻¹
- A motor-cyclist drives a motor cycle in a vertical circle. His minimum velocity
- In the half wave rectifier circuit operating from 50 Hz mains frequency,
- An electron in a circular orbit of radius 0.05 nm performs 10¹⁶ rev/s. The magnetic
Topics: Atoms and Nuclei (136)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply