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If the binding energy of the nucleon in ₃⁷Li and ₂⁴He nuclei are 5.60 MeV and 7.06 MeV respectively, then in the reaction: p+₃⁷Li→2 ₂⁴He, energy of proton must be
Options
(a) 39.2 MeV
(b) 28.24 MeV
(c) 17.28 MeV
(d) 1.46 MeV
Correct Answer:
17.28 MeV
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
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Topics: Atoms and Nuclei
(136)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- λ₁ and λ₂ are used to illuminate the slits. β₁ and β₂ are the corresponding fringe
- The young’s modulus of steel is twice that of brass. Two wires of same length
- The induced emf in a coil of 10 H inductance in which current varies
- Astigmatism is corrected by using
- A particle of mass 1.96×10⁻¹⁵ kg is kept in equilibrium between two horizontal metal
Topics: Atoms and Nuclei (136)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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