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If temperature of gas increases from 27°C to 927°C, the kinetic energy will be
Options
(a) double
(b) half the initial value
(c) one fourth
(d) four times
Correct Answer:
four times
Explanation:
T₁ = 27⁰C =300K
T₂ =927⁰C =1200K
V(rms)( root mean square velocity )= √3RT/M
KE₁ = 2/1×m×V² rms
KE₂= 2/1×m× 3R×1200/m
=4KE₁ .
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Topics: Behavior of Perfect Gas and Kinetic Theory
(34)
Subject: Physics
(2479)
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