| ⇦ |
| ⇨ |
If temperature of gas increases from 27°C to 927°C, the kinetic energy will be
Options
(a) double
(b) half the initial value
(c) one fourth
(d) four times
Correct Answer:
four times
Explanation:
T₁ = 27⁰C =300K
T₂ =927⁰C =1200K
V(rms)( root mean square velocity )= √3RT/M
KE₁ = 2/1×m×V² rms
KE₂= 2/1×m× 3R×1200/m
=4KE₁ .
Related Questions: - The velocity of a particle at an instant is 10 ms⁻¹.After 3 s its velocity will become
- 24 cells of emf 1.5 V each having internal resistance of 1 ohm are connected
- A small oil drop of mass 10⁻⁶kg is hanging in at rest between two plates seperated
- In adiabatic expansion, product of PV
- An automobile engine develops 100 kW when rotating at a speed of 1800 rev/min
Topics: Behavior of Perfect Gas and Kinetic Theory
(34)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The velocity of a particle at an instant is 10 ms⁻¹.After 3 s its velocity will become
- 24 cells of emf 1.5 V each having internal resistance of 1 ohm are connected
- A small oil drop of mass 10⁻⁶kg is hanging in at rest between two plates seperated
- In adiabatic expansion, product of PV
- An automobile engine develops 100 kW when rotating at a speed of 1800 rev/min
Topics: Behavior of Perfect Gas and Kinetic Theory (34)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply